Privacy Policy. Skip to main content. Waves and Vibrations. Search for:. Key Terms elasticity : The property by virtue of which a material deformed under the load can regain its original dimensions when unloaded. Elastic Potential Energy If a force results in only deformation, with no thermal, sound, or kinetic energy, the work done is stored as elastic potential energy.
Learning Objectives Express elastic energy stored in a spring in a mathematical form. Key Takeaways Key Points In order to produce a deformation, work must be done. Deformation can also be converted into thermal energy or cause an object to begin oscillating. Key Terms deformation : A transformation; change of shape. Licenses and Attributions. These are delivered one step at a time, and are accessible on mobile, tablet and desktop, so you can fit learning around your life. You can unlock new opportunities with unlimited access to hundreds of online short courses for a year by subscribing to our Unlimited package.
Build your knowledge with top universities and organisations. Learn more about how FutureLearn is transforming access to education. Learn more about this course. Share this post. Q1 E : If a mass of normalsize 10 kg on a heavy industrial spring of normalsize cm creates an extension of normalsize 3 mm, then how much extension would be caused by normalsize 15 kg?
How much mass would we have to load onto the original spring to get an extension of normalsize 5 mm? But behind this law is another law which is a fine example of an inverse proportionality.
What happens if we cut this spring into two equally sized pieces? More generally, the spring constant of a spring is inversely proportional to the length of the spring, assuming we are talking about a spring of a particular material and thickness. So suppose we cut the spring in the example above exactly in two, creating two shorter springs each of length normalsize 3 cm. One of the smaller springs will have a spring constant which is twice the original. That is because the spring constant and the length of the spring are inversely proportional.
That means that the original mass of normalsize 30 gm will only yield a stretch of normalsize 1 mm on the shorter spring. The larger the spring constant, the smaller the extension that a given force creates. Hopefully this makes intuitive sense — it should not be a surprise.
That is why you always need a free body diagram, and consistent conventions in order to get the correct signs in the balance equations. Sign up to join this community. The best answers are voted up and rise to the top. Stack Overflow for Teams — Collaborate and share knowledge with a private group.
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